Integrand size = 22, antiderivative size = 139 \[ \int \sqrt {a+b \log \left (c \left (d (e+f x)^p\right )^q\right )} \, dx=-\frac {\sqrt {b} e^{-\frac {a}{b p q}} \sqrt {p} \sqrt {\pi } \sqrt {q} (e+f x) \left (c \left (d (e+f x)^p\right )^q\right )^{-\frac {1}{p q}} \text {erfi}\left (\frac {\sqrt {a+b \log \left (c \left (d (e+f x)^p\right )^q\right )}}{\sqrt {b} \sqrt {p} \sqrt {q}}\right )}{2 f}+\frac {(e+f x) \sqrt {a+b \log \left (c \left (d (e+f x)^p\right )^q\right )}}{f} \]
-1/2*(f*x+e)*erfi((a+b*ln(c*(d*(f*x+e)^p)^q))^(1/2)/b^(1/2)/p^(1/2)/q^(1/2 ))*b^(1/2)*p^(1/2)*Pi^(1/2)*q^(1/2)/exp(a/b/p/q)/f/((c*(d*(f*x+e)^p)^q)^(1 /p/q))+(f*x+e)*(a+b*ln(c*(d*(f*x+e)^p)^q))^(1/2)/f
Time = 0.05 (sec) , antiderivative size = 134, normalized size of antiderivative = 0.96 \[ \int \sqrt {a+b \log \left (c \left (d (e+f x)^p\right )^q\right )} \, dx=\frac {(e+f x) \left (-\sqrt {b} e^{-\frac {a}{b p q}} \sqrt {p} \sqrt {\pi } \sqrt {q} \left (c \left (d (e+f x)^p\right )^q\right )^{-\frac {1}{p q}} \text {erfi}\left (\frac {\sqrt {a+b \log \left (c \left (d (e+f x)^p\right )^q\right )}}{\sqrt {b} \sqrt {p} \sqrt {q}}\right )+2 \sqrt {a+b \log \left (c \left (d (e+f x)^p\right )^q\right )}\right )}{2 f} \]
((e + f*x)*(-((Sqrt[b]*Sqrt[p]*Sqrt[Pi]*Sqrt[q]*Erfi[Sqrt[a + b*Log[c*(d*( e + f*x)^p)^q]]/(Sqrt[b]*Sqrt[p]*Sqrt[q])])/(E^(a/(b*p*q))*(c*(d*(e + f*x) ^p)^q)^(1/(p*q)))) + 2*Sqrt[a + b*Log[c*(d*(e + f*x)^p)^q]]))/(2*f)
Time = 0.58 (sec) , antiderivative size = 140, normalized size of antiderivative = 1.01, number of steps used = 7, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.273, Rules used = {2895, 2836, 2733, 2737, 2611, 2633}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \sqrt {a+b \log \left (c \left (d (e+f x)^p\right )^q\right )} \, dx\) |
\(\Big \downarrow \) 2895 |
\(\displaystyle \int \sqrt {a+b \log \left (c \left (d (e+f x)^p\right )^q\right )}dx\) |
\(\Big \downarrow \) 2836 |
\(\displaystyle \frac {\int \sqrt {a+b \log \left (c d^q (e+f x)^{p q}\right )}d(e+f x)}{f}\) |
\(\Big \downarrow \) 2733 |
\(\displaystyle \frac {(e+f x) \sqrt {a+b \log \left (c d^q (e+f x)^{p q}\right )}-\frac {1}{2} b p q \int \frac {1}{\sqrt {a+b \log \left (c d^q (e+f x)^{p q}\right )}}d(e+f x)}{f}\) |
\(\Big \downarrow \) 2737 |
\(\displaystyle \frac {(e+f x) \sqrt {a+b \log \left (c d^q (e+f x)^{p q}\right )}-\frac {1}{2} b (e+f x) \left (c d^q (e+f x)^{p q}\right )^{-\frac {1}{p q}} \int \frac {\left (c d^q (e+f x)^{p q}\right )^{\frac {1}{p q}}}{\sqrt {a+b \log \left (c d^q (e+f x)^{p q}\right )}}d\log \left (c d^q (e+f x)^{p q}\right )}{f}\) |
\(\Big \downarrow \) 2611 |
\(\displaystyle \frac {(e+f x) \sqrt {a+b \log \left (c d^q (e+f x)^{p q}\right )}-(e+f x) \left (c d^q (e+f x)^{p q}\right )^{-\frac {1}{p q}} \int \exp \left (\frac {a+b \log \left (c d^q (e+f x)^{p q}\right )}{b p q}-\frac {a}{b p q}\right )d\sqrt {a+b \log \left (c d^q (e+f x)^{p q}\right )}}{f}\) |
\(\Big \downarrow \) 2633 |
\(\displaystyle \frac {(e+f x) \sqrt {a+b \log \left (c d^q (e+f x)^{p q}\right )}-\frac {1}{2} \sqrt {\pi } \sqrt {b} \sqrt {p} \sqrt {q} (e+f x) e^{-\frac {a}{b p q}} \left (c d^q (e+f x)^{p q}\right )^{-\frac {1}{p q}} \text {erfi}\left (\frac {\sqrt {a+b \log \left (c d^q (e+f x)^{p q}\right )}}{\sqrt {b} \sqrt {p} \sqrt {q}}\right )}{f}\) |
(-1/2*(Sqrt[b]*Sqrt[p]*Sqrt[Pi]*Sqrt[q]*(e + f*x)*Erfi[Sqrt[a + b*Log[c*d^ q*(e + f*x)^(p*q)]]/(Sqrt[b]*Sqrt[p]*Sqrt[q])])/(E^(a/(b*p*q))*(c*d^q*(e + f*x)^(p*q))^(1/(p*q))) + (e + f*x)*Sqrt[a + b*Log[c*d^q*(e + f*x)^(p*q)]] )/f
3.5.62.3.1 Defintions of rubi rules used
Int[(F_)^((g_.)*((e_.) + (f_.)*(x_)))/Sqrt[(c_.) + (d_.)*(x_)], x_Symbol] : > Simp[2/d Subst[Int[F^(g*(e - c*(f/d)) + f*g*(x^2/d)), x], x, Sqrt[c + d *x]], x] /; FreeQ[{F, c, d, e, f, g}, x] && !TrueQ[$UseGamma]
Int[(F_)^((a_.) + (b_.)*((c_.) + (d_.)*(x_))^2), x_Symbol] :> Simp[F^a*Sqrt [Pi]*(Erfi[(c + d*x)*Rt[b*Log[F], 2]]/(2*d*Rt[b*Log[F], 2])), x] /; FreeQ[{ F, a, b, c, d}, x] && PosQ[b]
Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.), x_Symbol] :> Simp[x*(a + b *Log[c*x^n])^p, x] - Simp[b*n*p Int[(a + b*Log[c*x^n])^(p - 1), x], x] /; FreeQ[{a, b, c, n}, x] && GtQ[p, 0] && IntegerQ[2*p]
Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_), x_Symbol] :> Simp[x/(n*(c*x ^n)^(1/n)) Subst[Int[E^(x/n)*(a + b*x)^p, x], x, Log[c*x^n]], x] /; FreeQ [{a, b, c, n, p}, x]
Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_.), x_Symbol] : > Simp[1/e Subst[Int[(a + b*Log[c*x^n])^p, x], x, d + e*x], x] /; FreeQ[{ a, b, c, d, e, n, p}, x]
Int[((a_.) + Log[(c_.)*((d_.)*((e_.) + (f_.)*(x_))^(m_.))^(n_)]*(b_.))^(p_. )*(u_.), x_Symbol] :> Subst[Int[u*(a + b*Log[c*d^n*(e + f*x)^(m*n)])^p, x], c*d^n*(e + f*x)^(m*n), c*(d*(e + f*x)^m)^n] /; FreeQ[{a, b, c, d, e, f, m, n, p}, x] && !IntegerQ[n] && !(EqQ[d, 1] && EqQ[m, 1]) && IntegralFreeQ[ IntHide[u*(a + b*Log[c*d^n*(e + f*x)^(m*n)])^p, x]]
\[\int \sqrt {a +b \ln \left (c \left (d \left (f x +e \right )^{p}\right )^{q}\right )}d x\]
Exception generated. \[ \int \sqrt {a+b \log \left (c \left (d (e+f x)^p\right )^q\right )} \, dx=\text {Exception raised: TypeError} \]
Exception raised: TypeError >> Error detected within library code: inte grate: implementation incomplete (constant residues)
\[ \int \sqrt {a+b \log \left (c \left (d (e+f x)^p\right )^q\right )} \, dx=\int \sqrt {a + b \log {\left (c \left (d \left (e + f x\right )^{p}\right )^{q} \right )}}\, dx \]
\[ \int \sqrt {a+b \log \left (c \left (d (e+f x)^p\right )^q\right )} \, dx=\int { \sqrt {b \log \left (\left ({\left (f x + e\right )}^{p} d\right )^{q} c\right ) + a} \,d x } \]
\[ \int \sqrt {a+b \log \left (c \left (d (e+f x)^p\right )^q\right )} \, dx=\int { \sqrt {b \log \left (\left ({\left (f x + e\right )}^{p} d\right )^{q} c\right ) + a} \,d x } \]
Timed out. \[ \int \sqrt {a+b \log \left (c \left (d (e+f x)^p\right )^q\right )} \, dx=\int \sqrt {a+b\,\ln \left (c\,{\left (d\,{\left (e+f\,x\right )}^p\right )}^q\right )} \,d x \]